WebConsider a relation R (A,B,C,D,E,F,G,H) with the following functional dependencies: A → BCD AD → E EFG → H F → GH (a) Based on these functional dependencies, there is one minimal key for R. What is it? (b) One of the four functional dependencies can be removed without altering the key. Which one? 5. WebConsider the schema R = (A, B, C, D, E, G) and the set F of functional dependencies: AB → CD B → D DE → B DEG → AB AC → DE R is not in BCNF for many reasons, one of …
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WebGet Edredo App. Download Edredo to keep connected on the go WebTrue False. With regard to composition of relations, If S and R are both anti-reflexive, then s∘r is anti-reflexive. True False.
WebConsider the schema R=(A, B, C, D, E, G) and the set F of functional dependencies: 1 AB+ CD BD DE B DEG → AB AC DE R is not in BCNF for many reasons, one of which arises … Web(1) To determine if the two sets F and G are equivalent or not, we need to check if each functional dependency in F can be derived from G and vice versa. Starting with F: A → B can be derived from G by transitivity: A → BC (G), BC …
WebJun 28, 2024 · Find the highest normal form of a relation R (A,B,C,D,E) with FD set {B->A, A->C, BC->D, AC->BE} Step 1. As we can see, (B) + = {B,A,C,D,E}, so B will be candidate key. B can be derived from AC using AC->B (Decomposing AC->BE to AC->B and AC->E). So AC will be super key but (C) + = {C} and (A) + = {A,C,B,E,D}. WebOct 30, 2024 · Consider the universal relation R= {A,B,C,D,E,F,G,H,I,J} and a set of functional dependencies F= { {AB→ C}, { A → DE}, { B→ F}, {F→ GH}, {D→ IJ}}. What is the key for R? Decompose R into 2NF, then 3NF relations.
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WebSep 18, 2024 · Given a relation R (A, B, C, D, E, F) and set of FDs F: {A → BC, E → CF, B → E, CD → EF} Find out closure of {A, B}+ Step-1: Result = AB Step-2: First loop Result = ABC for A → BC, A ⊆ Result so Result = Result ∪ BC. Result = ABC for E→ CF, E ∉ Result so Result = Result. snowpiercer tv show season 2 where to watchWebExpert Answer Transcribed image text: = Consider the schema R = (A, B, C, D, E, G) and the set F of functional depen- dencies: AB → CD ADE → GDE B – GC G → DE Use the 3NF decomposition algorithm to generate a 3NF decomposition of R, and show your work. This means: a. A list of all candidate keys b. snowpiercer tv show vs movieWeb(b) [12 points] Find a minimal cover for the relation schema R (A, B,C, D, E, F, G) with the set F = AB → C, C → A, BC → D, ACD → B, D → EG, BE → C, CG → BD, CE → G of (a) [10 points] Find a minimal cover for the relation schema R (A, B,C, D, E, F, G) with the set F = {A → DE, BCE → EG, E → C, DG → EF} of functional dependencies. Show each step. snowplanet graboneWebFeb 23, 2024 · A relation R2 (A,B,C,D) having two FD sets FD1 = {A->B, B->C,A->C} and FD2 = {A->B, B->C, A->D} Step 1. Checking whether all FDs of FD1 is present in FD2 A->B in set FD1 is present in set FD2. B->C in set FD1 is also present in set FD2. A->C is present in FD1 but not directly in FD2 but we will check whether we can derive it or not. snowpine lodge holiday valleyWebDec 5, 2024 · Answer: relation of FDs are {a, b, d, h}. From these all but {h} seem plausibly part of keys. Calculating the closures of likely candidates gives: snowpiercer tv show watch onlineWebQuestion: Consider the schema R = (A, B, C, D, E, G) and the set of functional dependencies: AB → CD ADE → GDE B → GC G → DE 1. Is R in BCNF? Why or why not ... snowpinions 2020WebMay 30, 2024 · GATE Question: Consider a relation scheme R = (A, B, C, D, E, H) on which the following functional dependencies hold: {A–>B, BC–> D, E–>C, D–>A}. What are the candidate keys of R? [GATE 2005] (a) … snowpiercer tv show season 4 release date